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75 lines
1.7 KiB
XML
75 lines
1.7 KiB
XML
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
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<root>
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<name>& (bitwise AND)</name>
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<category>Math</category>
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<subcategory>Bitwise Operators</subcategory>
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<usage>Web & Application</usage>
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<example>
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<image></image>
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<code>
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int a = 207; // In binary: 11001111
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int b = 61; // In binary: 00111101
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int c = a & b; // In binary: 00001101
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println(c); // Prints "13", the decimal equivalent to 00001101
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</code>
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</example>
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<example>
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<image></image>
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<code>
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color argb = color(204, 204, 51, 255);
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// The sytax "& 0xFF" compares the binary
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// representation of the two values and
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// makes all but the last 8 bits into a 0.
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// "0xFF" is 00000000000000000000000011111111
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int a = argb >> 24 & 0xFF;
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int r = argb >> 16 & 0xFF;
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int g = argb >> 8 & 0xFF;
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int b = argb & 0xFF;
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fill(r, g, b, a);
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rect(30, 20, 55, 55);
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</code>
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</example>
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<description>
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Compares each corresponding bit in the binary representation of the values. For each comparison two 1's yeild 1, 1 and 0 yeild 0, and two 0's yeild 0. This is easy to see when we look at the binary representation of numbers<br /><br /><pre> 11010110 // 214<br />& 01011100 // 92<br /> --------<br /> 01010100 // 84</pre><br />To see the binary representation of a number, use the <b>binary()</b> function with <b>println()</b>.
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</description>
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<syntax>
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<c>value</c> & <c>value2</c>
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</syntax>
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<parameter>
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<label>value1</label>
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<description>int, char, byte</description>
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</parameter>
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<parameter>
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<label>value2</label>
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<description>int, char, byte</description>
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</parameter>
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<returns></returns>
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<related>
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| (bitwise OR)
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binary()
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</related>
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<availability>1.0</availability>
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<type>Operator</type>
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<partof>PDE</partof>
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<level>Extended</level>
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</root>
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